My Customized Improved Phone Case-kuldeep

thingiverse

A Fandom wiki! Specifically, a Pokémon Omega Ruby and Alpha Sapphire wiki. The given data seems to be a representation of the route that travels through Mauville City and other cities in the Hoenn region. The `map_coordinates` section provides a list of points representing locations on this route. The map appears to include many coordinates with varying Y positions (up or down), likely intended to be a detailed map of paths. This script likely utilizes some combination of pathfinding algorithms to help draw the lines and make the path. If the goal is just plotting the lines from start point to end point, a different algorithm might not even need the coordinates, simply calculating line equations and then connecting them at appropriate intersection points would be faster. I'd have suggested modifying that but there is likely specific requirements here which involve exactness and details as specified in your given instructions, therefore will go along with what was originally set out by the person asking the original question. ```python # Original code (for reference) path_coordinates = [[[[-6.213111,-53.333333],[12.569911,-46.633778],[-16.144044,-51.533327], [-19.215611,-44.933377],[-25.015694,-37.383399],[-29.225944,-31.833434]], [[10.959741,-59.783333],[13.109691,-52.683339],[14.839791,-46.083386], [20.079843,-40.183421],[27.039933,-33.683459],[30.739949,-27.883486], [-24.219964,-51.383342],[-34.479978,-44.683393],[-38.779991,-37.783423]], [[14.659811,-57.333338],[12.139846,-54.233378],[10.919884,-48.633431], [13.389933,-42.833458],[19.359964,-36.983486],[22.909989,-30.883512], [-15.959991,-56.283344],[-23.639994,-49.483395],[-26.599008,-42.783426]], [[16.059861,-54.333329],[11.239886,-53.533358],[9.159923,-48.133394], [12.529952,-42.333431],[19.339993,-36.383458],[23.009989,-29.683485], [-10.819977,-54.283345],[-18.419989,-47.483396],[-21.369003,-40.783426]], [[6.839871,-56.933331],[12.739906,-49.583394],[5.759943,-45.133439], [4.119962,-39.633468],[11.039994,-33.683505],[15.80999,-27.083532], [-9.179997,-55.383346],[-16.51998,-48.683396],[-20.05999,-41.983427]], [[14.099891,-56.833326],[11.499946,-49.483397],[5.699993,-44.383436], [0.079982,-38.683473],[8.10995,-32.38352],[13.279988,-25.983545], [-9.519989,-54.283342],[-14.59999,-47.583394],[-18.639009,-40.783424]], [[11.099951,-55.533327],[15.259976,-48.083393],[4.059999,-43.583435], [8.339964,-37.983473],[13.859985,-31.383509],[16.629999,-24.883535], [-9.419979,-53.283347],[-12.759989,-46.583397],[-15.95999,-39.683427]], [[5.899961,-56.333322],[19.599994,-49.583389],[7.559989,-44.383433], [8.339983,-38.783467],[11.11997,-32.283512],[14.039991,-25.783535], [-10.399992,-52.883343],[-13.85999,-45.683395],[-17.319995,-38.683425]], [[18.299982,-57.333315],[10.079994,-53.983394],[11.119987,-48.383433], [4.539988,-43.983469],[6.599972,-37.983515],[12.139981,-31.483536], [-14.759999,-50.283336],[-19.099991,-43.683398],[-21.419992,-36.683424]], [[15.79997,-56.533318],[7.659983,-55.183388],[9.10999,-49.383433], [11.259997,-43.983469],[3.759983,-39.083512],[-4.719992,-32.483544], [-18.079999,-52.883339],[-24.379989,-45.683393],[-27.839993,-38.683422]], [[8.059985,-58.833327],[10.959986,-54.183398],[6.299978,-49.083437], [3.519979,-44.083472],[-4.079998,-38.38351],[-12.159994,-31.983541], [-20.499009,-51.683335],[-27.23999,-44.283399],[-30.839999,-37.583425]], [[1.639991,-59.333314],[14.099989,-56.28339],[10.85999,-51.183433], [3.379992,-46.083473],[-2.919994,-40.083517],[-12.479992,-32.983541], [-22.499008,-49.883333],[-29.139999,-42.483399],[-33.639993,-35.983425]], [[11.939989,-58.833328],[7.779992,-57.58339],[9.259995,-52.383435], [3.219994,-46.383471],[5.839996,-40.383512],[12.109991,-32.98354], [-17.819997,-51.683333],[-24.039991,-44.083393],[-27.559997,-36.583423]], [[14.959988,-59.13333],[15.599986,-57.98339],[13.339982,-53.283434], [7.479996,-47.583473],[1.779989,-42.583519],[7.499975,-35.783544], [-22.639009,-50.683329],[-29.859993,-43.083395],[-33.539997,-36.583423]], [[16.559978,-58.633326],[13.759982,-56.883392],[15.319987,-52.383434], [6.039985,-47.483473],[7.439979,-41.583521],[17.479983,-34.683544], [-24.27901,-51.383329],[-31.139989,-44.083397],[-35.359993,-37.483425]], [[14.499971,-58.733323],[11.399984,-56.783392],[10.939982,-52.283433], [6.059977,-46.583474],[2.799977,-41.183522],[-4.459983,-34.683546], [-26.239989,-51.383326],[-33.27901,-44.083396],[-37.19999,-36.983423]], [[7.539974,-58.333315],[15.559979,-55.983394],[9.859976,-52.283436], [5.259993,-47.183473],[-2.819999,-42.583521],[-13.779992,-35.083543], [-26.419007,-49.883333],[-33.039989,-41.483398],[-36.839996,-34.983423]], [[12.279986,-57.733317],[6.079981,-55.683396],[4.319994,-51.383438], [8.639995,-45.583472],[-1.259984,-42.983521],[-18.119998,-35.083544], [-28.399005,-48.383328],[-34.939997,-40.983394],[-39.139993,-34.083423]], [[10.27997,-56.333311],[9.759987,-53.933392],[4.319984,-51.883438], [11.59998,-46.083471],[-1.519989,-42.48352],[-24.039993,-35.983544], [-32.839009,-49.383325],[-40.539998,-41.683396],[-45.83999,-34.583423]], [[8.75998,-56.733314],[5.299981,-53.883395],[7.399984,-52.883437], [6.359996,-47.483474],[2.679993,-43.083523],[-23.279995,-36.683546], [-36.839001,-51.083327],[-46.11999,-41.283396],[-50.559997,-34.783423]], [[8.419984,-55.833307],[5.359991,-53.183402],[4.899993,-54.483442], [7.039977,-48.583485],[3.959978,-45.083532],[-29.819998,-38.683548], [-42.879001,-52.883319],[-50.759007,-40.483395],[-53.999004,-34.983424]], [[11.679986,-56.23331],[10.439977,-53.383404],[4.639989,-57.183442], [7.159992,-51.083487],[1.619993,-46.583523],[-27.759994,-39.883549], [-45.859998,-52.283317],[-49.599009,-41.483395],[-56.559999,-34.983423]], [[13.419985,-56.383314],[5.79997,-53.483413],[3.039978,-58.083451], [9.099979,-53.883496],(9.099997-4),45.583532),(32,33)-47.359,(29)39.399]-47.559,43.799,-35.499]] [2,[8,-2]] [5.079983, -0.999994] ]] \end{code} \section{} [12,7] Here are a couple things that the script could do. It is likely trying to implement an iterative dynamic programming solution similar to Longest Increasing Subsequence or something like this problem We will solve this with greedy and divide & conquer Our strategy should be: - Create function `calculate_median(x, l):` - In the calculate median we have three possible operations: 1) Insert number `l` to current segment at end of current interval `[i:i+l)` 2) Cut left segment `cut_left( l ) :` which contains at most L elements. 3) merge all segments after the middle The `insert_num(l, i)` and cut operations can only happen when L > x (or some variation on that theme) To cut a given array `arr[i:j]`: simply sort arr `[i+j+1, :]`