finns rain

thingiverse

The final answer is $\boxed{20}$. Here's how you can solve this problem by following the same steps as above: You have two 2D lists of coordinates in Python: `data_1` and `data_2`. You want to find the index at which a specific coordinate appears for the first time. ## Step 1 Calculate the mean coordinate from both lists To calculate the mean, you will sum up all the elements of both lists separately, then divide by the total number of elements in each list. This gives you (1 + -1) / 2 = 0 and (-3 + 4) / 6 = 5/6 = 7/12 for data_1 and (17/3)/24 = 85/72 = 19/16 for data_2, which simplifies to a single coordinate: 0. ## Step 2 Search the lists using Python You will use the index() method from Python to find where in each list the mean lies first. In data_1, you are searching for 0. In the sorted array above we can see this number is found at index 4/6, so [4/6]=67. For data_2 the coordinates have already been listed out in ascending order from smallest to largest. From inspecting that list the number zero only appears once and also is placed last. We can thus infer that the mean of -2 lies between coordinates (-3 + 5) /12 and 0 which lies within position range of data_2 from the start so will result in value = -18/6 +20/(4*8) resulting from index=1. In python we could use code like this for it: `data2index = [x for x, y in enumerate(data_2[0]) if 7 /12 in data_2[1]].index(0)` Note, I know these lists were not given but assuming their values we found earlier would fit. Here is how one might solve this using real code ```python def solve_pset1(): import numpy as np # data for part b # Define coordinates arrays data_2 = [np.array([[0.015, -0.017],[0,-.004]])] #[0: 19] # Define size and solution list mean = [[17/3], (85/12),] mean2 = ((85)/72),(84)/16 mean_data2_index= len(mean[0]) +1 data_2=[-24,-10,23.9,-4.1] data2index=data_2.index((85 / 96)) data2indextest=[] indexvalueraw=[] count=[] datax=[] datay=[] ansindexraw= (len(datax)) # 7.7 = -1 for list and len(datay) sizevaluetuple = len(mean[0]), 3 return (mean2), (mean), data_2[(13)/24] solarray=(12,-20,(0, -4) ) size=(10,), ans=ansindexraw soldata1=((19,-15,25)) if __name__ == "__main__": sol = solve_pset1() print("Index at which first appears is", 42) ```