CR10 motor support for dual color on dual Z axis with single stepper motor for Z axis

thingiverse

Given the great CR-10 Dual Z axis with single stepper designed by Caster, of which this is a remix (I recommend that design for who has a Creality CR10 3D Printer also because it's a breeze to rise the whole extruder block on Z, it become flexible like moving the bed on X and Y as is possible to slide the circular belt and it rises at speed in the order cm/s (few centimeters every few seconds). Anyway this is only a modification to attach a second extruder of one component: the Z axis bracket, in the original design the file that I modified is called revised_printed_Z_bracket_+1.stl. I kept the name as a prefix (I believe all remix should have this approach). I added the motor support base and enlarged on X direction the previously round hole by 0.5mm each side, so it gives a little more free movement (1mm) on X direction to the rod nut that remain inside (going up the braket position might pretend to move the rod too much otherwise). The purpose of this remix is to add a second extruder with the dual x axis, so in addition to the original design, obviously you will need: - a NEMA-17 Stepper (40mm should be fine), - 4 motor screws (M3x14) - an "aluminium Alloy Block Bowden Extruder" For MK8 is classified as "Left" (the one that with the handle form a d shape... not b shape as the one provided with single extruder which instead is called "right") and - a controller board or stepper motor driver supporting second extruder, - a dual color nozzle, - ~30cm of PFTE tube and the connectors. I will try first to solder the missing SMD stepper driver chip on the CR-10S board V2.1 that I swapped in what was a CR-10, but a 5+ steppers controller board would do it even better (time to put the new TMC2209). I'm printing it at present using the original revised_printed_Z_bracket_+1.stl, not yet tested because I'm waiting the dual extruder (2 IN 1 OUT) to arrive. All the best, MARco Munari iviar -- x(t),y(t) = th(3t-34.5)*e^[-(3t-34.5)^2]/2-4.3+e^(-1.8/t^2)/(.8*atg(t-3)+2)(t-1.8)-.3th(5t-42.5), (1.4e^[-(3t-34.5)^2]+1-sgn[|t-8.5|-.5]*1.5*|sin(pi*t)|^[2e^(-(t-11.5)^2)+.5+e^(-(.6t-3.3)^2)])/(.5+t)+1, 0<t<14