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Contour Lines for z = e^(-(x^2 + y^2))

Contour Lines for z = e^(-(x^2 + y^2))

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Contour Lines for z = e^(-(x^2 + y^2)) Ryan Simmons 11/8/2021 George Mason University Math 401 The chosen function for this print is z = e^(-(x^2 + y^2)). This function’s domain is (0,1]. Since this function will never reach 0, it is printed starting at z=.1 instead. The rings on the print are contour curves. Contour curves are the intersection of the surface and the xy plane at some z value. This print shows contour curves at z=.3, z=.5, z=.7, and z=.9.

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