Adjustable LED base

cults3d

Human: Adjustable LED base Many people have asked me about the way I light my lampshades. I simply use a red, green and blue LED placed in an offset position from each other. My old LED bases are made of wood and feature a simple design. You can see one in the picture. Now, I have created one that can be printed out. I also took the liberty to make the distance between the LEDs adjustable. The distance between them can be adjusted by turning the outer ring of the base. The white adjustable LED base in the pictures has 3W LEDs and they come with their own heatsink. They work well, but get really hot. They must be able to radiate heat. So I recommend making a hole into the base of your spiral vase mode lamp shade. Otherwise, they will melt the plastic. If you are using 1W LEDs without their own heatsink, you have to glue them to an aluminum plate with thermal glue. In the picture of the wooden base, you can see an example. Most of my lampshades' photos feature a base that includes 1W LEDs. Then there is the problem that there are many different types of LEDs available, and they are not all the same in voltage and current they use. So the resistors used may vary in resistance and voltage. It's very important to use the right resistor. The value of this resistor is defined by the voltage of your power supply, the voltage of the LED, and the current the LED will draw. In my case, I use a USB power adapter 2.1A, which means it has 5V. Most RED power LEDs operate at a voltage up to 2.3V. Most GREEN and BLUE power LEDs operate at a voltage up to 3.6V. The current of the LEDs is given by their manufacturer. Because I want to inspire people to do things themselves, I have included an example of how to calculate the resistor in one of the pictures. Below, I have calculated the resistors for 3W red, green and blue LEDs, and below that also for the 1W LEDs. BUT BEWARE! These resistor values only work with a 5V power supply. For the 3W heatsink ones, I have calculated for 700mA so the resistor will be something like: RED: voltage over resistor = 5V-2.3V=2.7V. R=U/I = 2.7V/0.7A=3.86Ω. P=UxI = 2.7x0.7=1.89W. I used in this case 8 33Ω /0.25W resistors in parallel. GREEN: voltage over resistor = 5V-3.6=1.4V. R=U/I = 1.4V/0.7A=2Ω. P=UxI =1.4x0.7=0.98W. I used in this case 5 10Ω /0.25W resistors in parallel. BLUE: voltage over resistor = 5V-3.6=1.4V. R=U/I = 1.4V/0.7A=2Ω. P=UxI =1.4x0.7=0.98W. I used in this case 5 10Ω /0.25W resistors in parallel. For the 1W ones without their own heatsink, I have calculated for 434mA so the resistor will be something like: RED: voltage over resistor = 5V-2.3V=2.7V. R=U/I = 2.7V/0.434A=6.23Ω. P=UxI = 2.7x0.434A=1.17W. I used in this case 6 33Ω /0.25W resistors in parallel. GREEN: voltage over resistor = 5V-3.6V=1.4V. R=U/I = 1.4V/0.434A=3.23Ω. P=UxI = 1.4Vx0.434A=0.61W. I used in this case 5 10Ω /0.25W resistors. BLUE: voltage over resistor = 5V-3.6V=1.4V. R=U/I = 1.4V/0.434A=3.23Ω. P=UxI = 1.4Vx0.434A=0.61W. I used in this case 5 10Ω /0.25W resistors. If you find all of this too much work, then you can just buy a standard LED driver. I will post a simple dimmable one soon.